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too complicated to be written here. Click on the link to download a text file. 

X(3), X(4) antipoints, see Table 77 

See Q125 for general explanations where Q129 is Q(X186). The radial center is X(5). The third polar of X(30) is K026. This means that the polar line of any point of K026 in the quartic is parallel to the Euler line. This is the case of the tangents at A, B, C to Q129 and this also shows that Q129 is bitangent at O, H to the Euler line. 
